Find Stella’s cost for a week when she sells no pizzas.The equation \(C=4p+25\) models the relation between her weekly cost, \(C\), in dollars and the number of pizzas, \(p\), that she sells. Stella has a home business selling gourmet pizzas. It is for the material and labor needed to produce each item. The variable cost depends on the number of units produced. This is the cost of rent, insurance, equipment, advertising, and other items that must be paid regularly. The fixed cost is always the same regardless of how many units are produced. The cost of running some types business has two components-a fixed cost and a variable cost. The \(T\)-intercept means that when the number of chirps is \(0\), the temperature is \(40°\). The value of the expression for specific values of x.\), means that the temperature Fahrenheit (\(F\)) increases \(1\) degree when the number of chirps, \(n\), increases by \(4\). Used to name an algebraic expression in the variable x, can also be used to denote Pair that is paired with a specified first component. Sometimes, we use a special notation to name the second component of an ordered In this form, we obtain values of y for given values of x as follows: Now, dividing each member by 2, we obtain Solve 2y - 3x = 4 explicitly for y in terms of x and obtain solutions for x = 0, Equal quantities are multiplied or divided by the same nonzero quantity.The same quantity is added to or subtracted from equal quantities.Where we solved first-degree equations in one variable. In general, we can write equivalentĮquations in two variables by using the properties we introduced in Chapter 3, Of Equation (1), in that way getting y by itself. We obtained Equation (2) by adding the same quantity, -2x, to each member We get the same pairings that we obtained using Equation (1) It is often easier to obtain solutions if equations are first expressed in such formīecause the dependent variable is expressed explicitly in terms of the independent In Equation (2), where y is by itself, we say that y is expressed explicitly in terms We can add -2x to both members of 2x + y = 4 to get The three pairings can now be displayed as the three ordered pairs Replacements for y are second components and hence y is the dependent variable.įor example, we can obtain pairings for equationīy substituting a particular value of one variable into Equation (1) and solving forįind the missing component so that the ordered pair is a solution to Ments for x are first components and hence x is the independent variable and ![]() ![]() If the variables x and y are used in an equation, it is understood that replace. It is convenient to speak of the variable associated with theįirst component of an ordered pair as the independent variable and the variableĪssociated with the second component of an ordered pair as the dependent variable. Of the variables, the value for the other variable is determined and thereforeĭependent on the first. In any particular equation involving two variables, when we assign a value to one Such pairings are sometimes shown in one of the following tabular forms. Some ordered pairs for t equal to 0, 1, 2, 3, 4, and 5 are With this agreement, solutions of theĮquation d - 40t are ordered pairs (t, d) whose components satisfy the equation. Second numbers in the pairs as components. ![]() We call such pairs of numbers ordered pairs, and we refer to the first and Order in which the first number refers to time and the second number refers toĭistance, we can abbreviate the above solutions as (1, 40), (2, 80), (3, 120), and If we agree to refer to the paired numbers in a specified ![]() The pair of numbers 1 and 40, considered together, is called a solution of theĮquation d = 40r because when we substitute 1 for t and 40 for d in the equation, The equation d = 40f pairs a distance d for each time t. In this chapter, we will deal with tabular and graphical representations. We have already used word sentences and equations to describe such relationships 4.Ě graph showing the relationship between time and distance.The distance traveled in miles is equal to forty times the number of hours traveled. In a certain length of time by a car moving at a constant speed of 40 miles per hour. As an example, let us consider the distance traveled The language of mathematics is particularly effective in representing relationshipsīetween two or more variables.
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